ship of mass 2 × 107 kg initially at rest is pulled by a force of 5 × 105 N through a distance of 2 m. Assuming that the resistance due to water is negligible, the speed of the ship is

Question

ship of mass 2 × 107 kg initially at rest is pulled by a force of 5 × 105 N through a distance of 2 m. Assuming that the resistance due to water is negligible, the speed of the ship is (A) 2 ms-1 (B) 0.01 ms-1 (C) 0.1 ms-1 (D) 1 ms-1

Tardigrade Admin · Accepted Answer

Given u=0 m =2 × 107 kg ; F=5 × 105 ; S=2 m From work -energy theorem W=(1/2) m v2-(1/2) m u2=F S (1/2) × 2 × 10-7 × v2=5 × 105 × 2 107 V2=106 V2=10-1 V=√10-1

Q. ship of mass $2 \times 1 0^{7} k g$ initially at rest is pulled by a force of $5 \times 1 0^{5} N$ through a distance of $2 m$ . Assuming that the resistance due to water is negligible, the speed of the ship is

$2 m s^{- 1}$

$0.01 m s^{- 1}$

$0.1 m s^{- 1}$

$1 m s^{- 1}$

$5 m s^{- 1}$

Given
$u = 0 m = 2 \times 1 0^{7} k g;$
$F = 5 \times 1 0^{5}; S = 2 m$
From work -energy theorem
$W = \frac{1}{2} m v^{2} - \frac{1}{2} m u^{2} = FS$
$\frac{1}{2} \times 2 \times 1 0^{- 7} \times v^{2} = 5 \times 1 0^{5} \times 2$
$1 0^{7} V^{2} = 1 0^{6}$
$V^{2} = 1 0^{- 1}$
$V = 1 0^{- 1}$

Q. ship of mass 2×107kg initially at rest is pulled by a force of 5×105N through a distance of 2m. Assuming that the resistance due to water is negligible, the speed of the ship is

2ms−1

0.01ms−1

0.1ms−1

1ms−1

5ms−1

Given u=0m=2×107kg; F=5×105;S=2m From work -energy theorem W=21​mv2−21​mu2=FS 21​×2×10−7×v2=5×105×2 107V2=106 V2=10−1 V=10−1​