Shape of Fe(CO)5 is

Question

Shape of Fe(CO)5 is (A) octahedral (B) square planar (C) trigonal bipyramidal (D) square pyramidal

Tardigrade Admin · Accepted Answer

In Fe(CO)5, the Fe-atom is in dsp3 hybridised state, therefore the shape of molecule is trigonal bipyramidal. The hybridisation is as follows: 26Fe = 1s2, 2s2 2p6, 3s2 3p6 3d6, 4s2 4p) In Fe(CO)5, the Fe-atom is

Q. Shape of $F e (CO)_{5}$ is

octahedral

square planar

trigonal bipyramidal

square pyramidal

In $F e (CO)_{5},$ the Fe-atom is in $d s p^{3}$ hybridised state, therefore the shape of molecule is trigonal bipyramidal.
The hybridisation is as follows : $_{26} F e = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{6}, 4 s^{2} 4 p^{)}$
In $F e (CO)_{5}$ , the Fe-atom is

Q. Shape of Fe(CO)5​ is