Self-ionisation of liquid ammonia occurs as 2NH3leftharpoons NH4++NH2-; K=10-10 In this solvent, an acid might be:

Question

Self-ionisation of liquid ammonia occurs as 2NH3leftharpoons NH4++NH2-; K=10-10 In this solvent, an acid might be: (A)  NH4+  (B)  NH3  (C) any species that will form NH4+  (D) all the above

Tardigrade Admin · Accepted Answer

NH3+NH3 leftharpoons underset beginsmallmatrix textproton textdonar text(acid) endsmallmatrix mathopNH4+ +NH2- Hence, NH4+ can donate proton and is an acid.

Q. Self-ionisation of liquid ammonia occurs as $2 N H_{3} ⇌ N H_{4}^{+} + N H_{2}^{-};$ $K = 10^{- 10}$ In this solvent, an acid might be:

$N H_{4}^{+}$

$N H_{3}$

any species that will form $N H_{4}^{+}$

all the above

$N H_{3} + N H_{3} ⇌ proton donar (acid) N H_{4}^{+} + N H_{2}^{-}$ Hence, $N H_{4}^{+}$ can donate proton and is an acid.

Q. Self-ionisation of liquid ammonia occurs as 2NH3​⇌NH4+​+NH2−​; K=10−10 In this solvent, an acid might be:

NH4+​

NH3​

any species that will form NH4+​