See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it ?

Question

See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it ? (A) ∈1-( i 1+ i 2) R + i 1 r 1=0 (B) ϵ1-( i 1+ i 2) R - i 1 r 1=0 (C) ϵ2- i 1 r 2-ε1- i 1 r 1=0 (D) -ϵ2-( i 1+ i 2) R + i 2 r 2=0

Tardigrade Admin · Accepted Answer

Apply Kirchhoff's second law, aslo called loop rule. The algebraic sum of the changes in potentail in complete transversal of a mesh (closed loop) is zero. le, ∑ V=0 Here, ε1=(i1+i2) R-i1 r1=0

Q. See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it ?

$\in_{1} - (i_{1} + i_{2}) R + i_{1} r_{1} = 0$

$ϵ_{1} - (i_{1} + i_{2}) R - i_{1} r_{1} = 0$

$ϵ_{2} - i_{1} r_{2} - ε_{1} - i_{1} r_{1} = 0$

$- ϵ_{2} - (i_{1} + i_{2}) R + i_{2} r_{2} = 0$

Apply Kirchhoff's second law, aslo called loop rule.
The algebraic sum of the changes in potentail in complete transversal of a mesh (closed loop) is zero.
le, $\sum V = 0$
Here, $ε_{1} = (i_{1} + i_{2}) R - i_{1} r_{1} = 0$

Q. See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it ?

∈1​−(i1​+i2​)R+i1​r1​=0

ϵ1​−(i1​+i2​)R−i1​r1​=0

ϵ2​−i1​r2​−ε1​−i1​r1​=0

−ϵ2​−(i1​+i2​)R+i2​r2​=0

Apply Kirchhoff's second law, aslo called loop rule. The algebraic sum of the changes in potentail in complete transversal of a mesh (closed loop) is zero. le, ∑V=0 Here, ε1​=(i1​+i2​)R−i1​r1​=0

$\in_{1} - (i_{1} + i_{2}) R + i_{1} r_{1} = 0$

$ϵ_{1} - (i_{1} + i_{2}) R - i_{1} r_{1} = 0$

$ϵ_{2} - i_{1} r_{2} - ε_{1} - i_{1} r_{1} = 0$

$- ϵ_{2} - (i_{1} + i_{2}) R + i_{2} r_{2} = 0$

Apply Kirchhoff's second law, aslo called loop rule.
The algebraic sum of the changes in potentail in complete transversal of a mesh (closed loop) is zero.
le, $\sum V = 0$
Here, $ε_{1} = (i_{1} + i_{2}) R - i_{1} r_{1} = 0$