Rohini satellite at a height of 500 km and INSAT-B at a height of 3600 km from surface of earth, then relation between their orbital velocity (vR, vI) is

Question

Rohini satellite at a height of 500 km and INSAT-B at a height of 3600 km from surface of earth, then relation between their orbital velocity (vR, vI) is (A) (vR > vI) (B) (vR< vI) (C) (vR=vI) (D) No relation

Tardigrade Admin · Accepted Answer

Orbital velocity of a satellite is given by

v_{o} = \frac{G M _{e}}{r}

where

G =

gravitational constant.

M_{e} =

mass of the earth

r =

distance of the satellite from the centre of the earth

∴ v_{o} \propto \frac{1}{r}

As the distance of INSAT-B from the centre of the earth is greater than the distance of Rohini from the centre of the earth

∴ v_{R} > v_{I}

Q. Rohini satellite at a height of $500 km$ and INSAT-B at a height of $3600 km$ from surface of earth, then relation between their orbital velocity $(v_{R}, v_{I})$ is

$(v_{R} > v_{I})$

$(v_{R} < v_{I})$

$(v_{R} = v_{I})$

No relation

Q. Rohini satellite at a height of 500km and INSAT-B at a height of 3600km from surface of earth, then relation between their orbital velocity (vR​,vI​) is

(vR​>vI​)

(vR​<vI​)

(vR​=vI​)

No relation

Q. Rohini satellite at a height of $500 km$ and INSAT-B at a height of $3600 km$ from surface of earth, then relation between their orbital velocity $(v_{R}, v_{I})$ is

$(v_{R} > v_{I})$

$(v_{R} < v_{I})$

$(v_{R} = v_{I})$