Resistance of a decinormal solution of a salt occupying a volume between platinum electrodes 1.8 cm apart and 5.4 cm2 in area was found to be 32 ohm. Equivalent conductivity of solution in S cm2 eq-1 is

Question

Resistance of a decinormal solution of a salt occupying a volume between platinum electrodes 1.8 cm apart and 5.4 cm2 in area was found to be 32 ohm. Equivalent conductivity of solution in S cm2 eq-1 is (A) 104.1 S cm2 eq-1 (B) 10.41 S cm2 eq-1 (C) 1.041 S cm2 eq-1 (D) 1041.0 S cm2 eq-1

Tardigrade Admin · Accepted Answer

Applying, k = (1/R) ×(l/a) =(1/32) ×(1.8/5.4) =0.01041 S cm-1 We know, ∧eq =K ×(1000/ textNormality) = 0.01041 ×(1000/1/10) =104.1 S cm2 eq-1

Q. Resistance of a decinormal solution of a salt occupying a volume between platinum electrodes $1.8 c m$ apart and $5.4 c m^{2}$ in area was found to be $32 o hm$ . Equivalent conductivity of solution in $S c m^{2} e q^{- 1}$ is

$104.1 S c m^{2} e q^{- 1}$

$10.41 S c m^{2} e q^{- 1}$

$1.041 S c m^{2} e q^{- 1}$

$1041.0 S c m^{2} e q^{- 1}$

Applying, $k = \frac{1}{R} \times \frac{l}{a}$
$= \frac{1}{32} \times \frac{1.8}{5.4} = 0.01041 S$ cm $^{- 1}$
We know, $\land_{e q} = K \times \frac{1000}{Normality} = 0.01041 \times \frac{1000}{1/10} = 104.1 S c m^{2} e q^{- 1}$

Q. Resistance of a decinormal solution of a salt occupying a volume between platinum electrodes 1.8cm apart and 5.4cm2 in area was found to be 32ohm. Equivalent conductivity of solution in Scm2eq−1 is

104.1Scm2eq−1

10.41Scm2eq−1

1.041Scm2eq−1

1041.0Scm2eq−1