Reaction of calgon with hard water containing Ca2+ ions produce

Question

Reaction of calgon with hard water containing Ca2+ ions produce (A) [Na2 CaP6O18 ]2-  (B) Ca2 (PO4 )3  (C) CaCO3  (D) CaSO4

Tardigrade Admin · Accepted Answer

Calgon is a trade name of a complex salt, sodium hexametaphosphate

(N a P O_{3})_{6} .

Calgon ionises to give a complex anion. The addition of calgon to hard water causes the calcium ions of hard water to displace sodium ions from the anion of calgon and form a complex with calgon.

(N a P O_{3})_{6}

or

N a_{2} (N a_{4} P_{6} O_{18}) ⟶ 2 N a^{+} + (Complex anion) N a_{4} P_{6} O_{18}^{2 -}

From hard water C a^{2 +} + Anion of calgon N a_{4} P_{6} O_{18}^{2 -} ⟶ 2 N a^{+} + Goes into solution C a N a_{2} P_{6} O_{18}^{2 -}

Q. Reaction of calgon with hard water containing $C a^{2 +}$ ions produce

$[Na X_{2} CaP X_{6} O X_{18}] X^{2 -}$

$Ca X_{2} (PO X_{4}) X_{3}$

$CaCO X_{3}$

$CaSO X_{4}$

Q. Reaction of calgon with hard water containing Ca2+ ions produce

[NaX2​ CaPX6​OX18​ ]X2−

CaX2​ (POX4​ )X3​

CaCOX3​

CaSOX4​

Q. Reaction of calgon with hard water containing $C a^{2 +}$ ions produce

$[Na X_{2} CaP X_{6} O X_{18}] X^{2 -}$

$Ca X_{2} (PO X_{4}) X_{3}$

$CaCO X_{3}$

$CaSO X_{4}$