Question

Propene reacts with $C{l}_2$ at $500°C$ the product is formed

• A. $1$ -chloro propene-$1$
• B. $2$-chloro propene-$1$
• C. $1,2$-dichloro propane
• D. $3$-chloro propene-$1$

Answer 1

Answer: (D)

$C{H}_3-CH=C{H}_2\underset{C{l}_2}{\overset{500^{\circ }C}{\to }}\stackrel{\underset{|}{\mathrm{Cl}}}{C}{H}_2-CH=C{H}_2$