Product obtain in reaction of t-butyl bromide with sodium methoxide is

Question

Product obtain in reaction of t-butyl bromide with sodium methoxide is (A) t- butyl methyl ether (B) Isobutylene (C) Sodium t- butoxide (D) Isobutane

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-zclbc6cts5i3.png" /> CH3ONa arrow CH3O-+Na+ methoxide ion (.CH3O-.) is a strong base, therefore it abstract proton from 3o alkyl halide and favours elimination reaction.

Q. Product obtain in reaction of t-butyl bromide with sodium methoxide is

$t -$ butyl methyl ether

Isobutylene

Sodium $t -$ butoxide

Isobutane

$C H_{3} ON a \to C H_{3} O^{-} + N a^{+}$

methoxide ion $(C H_{3} O^{-})$ is a strong base, therefore it abstract proton from $3^{o}$ alkyl halide and favours elimination reaction.

Q. Product obtain in reaction of t-butyl bromide with sodium methoxide is

t− butyl methyl ether

Isobutylene

Sodium t− butoxide

Isobutane

CH3​ONa→CH3​O−+Na+ methoxide ion (CH3​O−) is a strong base, therefore it abstract proton from 3o alkyl halide and favours elimination reaction.

$t -$ butyl methyl ether

Sodium $t -$ butoxide

$C H_{3} ON a \to C H_{3} O^{-} + N a^{+}$

methoxide ion $(C H_{3} O^{-})$ is a strong base, therefore it abstract proton from $3^{o}$ alkyl halide and favours elimination reaction.