Question

Potassium permanganate acts as an oxidant in alkaline and acidic media. The final products formed from $KMn{O}_4$ in the two conditions are respectively:

• A. $Mn{O}^{2-}$ and $M{n}^{3+}$
• B. $M{n}^{3+}$ and $M{n}^{2+}$
• C. $M{n}^{2+}$ and $M{n}^{3+}$
• D. $Mn{O}_2$ and $M{n}^{2+}$
• E. $M{n}^{2+},Mn{O}_2$

Answer 1

Answer: (D)

In acidic medium: $\stackrel{+7}{KMn{O}_4}\to \stackrel{+2}{MnS{O}_4}$
In weak basic medium: $KMn{O}_4\to Mn{O}_2$