Potassium, on burning in oxygen atmosphere, gives:

Question

Potassium, on burning in oxygen atmosphere, gives: (A) K2O  (B) K2O3 (C)  KO2 (D) K2O2

Tardigrade Admin · Accepted Answer

Burning K in excess O 2 gives the superoxide K O 2. Reaction with a large excess of metal will form the Oxide K 2 O. The superoxide reacts with water to form the peroxide, K 2 O 2, at low T and the oxide at higher T both with liberation of O 2.

Q. Potassium, on burning in oxygen atmosphere, gives:

$K_{2} O$

$K_{2} O_{3}$

$K O_{2}$

$K_{2} O_{2}$

Burning $K$ in excess $O_{2}$ gives the superoxide $K O_{2}$ . Reaction with a large excess of metal will form the Oxide $K_{2} O$ . The superoxide reacts with water to form the peroxide, $K_{2} O_{2}$ , at low $T$ and the oxide at higher $T$ both with liberation of $O_{2}$ .

Q. Potassium, on burning in oxygen atmosphere, gives:

K2​O

K2​O3​

KO2​

K2​O2​

Burning K in excess O2​ gives the superoxide KO2​. Reaction with a large excess of metal will form the Oxide K2​O. The superoxide reacts with water to form the peroxide, K2​O2​, at low T and the oxide at higher T both with liberation of O2​.

$K_{2} O$

$K_{2} O_{3}$

$K O_{2}$

$K_{2} O_{2}$

Burning $K$ in excess $O_{2}$ gives the superoxide $K O_{2}$ . Reaction with a large excess of metal will form the Oxide $K_{2} O$ . The superoxide reacts with water to form the peroxide, $K_{2} O_{2}$ , at low $T$ and the oxide at higher $T$ both with liberation of $O_{2}$ .