Question

Phenol $\underset{(ii)C{O}_2/140^{\circ }C}{\overset{(i)NaOH}{\to }}A\stackrel{H^{+}/H_{2}O}{\to }B\underset{C{H}_{3}COOH}{\overset{A{l}_2{O}_3}{\to }}C$
In this reaction, the end product C is

• A. salicylaldehyde
• B. salicylic acid
• C. phenyl acetate
• D. aspirin

Answer 1

Answer: (D)

Correct answer is (d) aspirin