Percentage of N in Kjeldahl' method =(1.4 × M × 2(V-(V1/2))/m) What does V1 represents in the above formula?

Question

Percentage of N in Kjeldahl' method =(1.4 × M × 2(V-(V1/2))/m) What does V1 represents in the above formula? (A) Volume of NaOH of molarity, M used for titration of excess of sulphuric acid (B) Volume of NaOH of normality, N used for titration of excess of sulphuric acid (C) Volume of H 2 SO 4 of molarity, M (D) Volume of H 2 SO 4 of normality, N

Tardigrade Admin · Accepted Answer

Correct answer is (a) Volume of NaOH of molarity, M used for titration of excess of sulphuric acid

Q. Percentage of $N$ in Kjeldahl' method
$= \frac{1.4 \times M \times 2 ( V - \frac{V _{1}}{2} )}{m}$
What does $V_{1}$ represents in the above formula?

Volume of $N a O H$ of molarity, $M$ used for titration of excess of sulphuric acid

Volume of $N a O H$ of normality, $N$ used for titration of excess of sulphuric acid

Volume of $H_{2} S O_{4}$ of molarity, $M$

Volume of $H_{2} S O_{4}$ of normality, $N$

Correct answer is (a) Volume of $N a O H$ of molarity, $M$ used for titration of excess of sulphuric acid

Q. Percentage of N in Kjeldahl' method =m1.4×M×2(V−2V1​​)​ What does V1​ represents in the above formula?

Volume of NaOH of molarity, M used for titration of excess of sulphuric acid

Volume of NaOH of normality, N used for titration of excess of sulphuric acid

Volume of H2​SO4​ of molarity, M

Volume of H2​SO4​ of normality, N