PCl5PCl3+Cl2 in this reversible reaction the moles of PCl5, PCl3, and Cl2 are a, b and c respectively and total pressure is P then value of Kp is:

Question

PCl5PCl3+Cl2 in this reversible reaction the moles of PCl5, PCl3, and Cl2 are a, b and c respectively and total pressure is P then value of Kp is: (A)  (bc/a).RT  (B)  (b/(a+b+c)).P  (C)  (bc.P/a(a+b+c))  (D)  (c/(a+b+c)).P

Tardigrade Admin · Accepted Answer

KP=(P'PCl3× P'Cl2/P'PCl5) =((b/(a+b+c)).P× (c/(a+b+c))× P/(a)(a+b+c)P) Kp=(bc. P/a(a+b+c)) undersetAcetylene mathopCH≡ CH xrightarrow[Ni]H2CH2=CH2

Q. $PC l_{5} PC l_{3} + C l_{2}$ in this reversible reaction the moles of $PC l_{5},$ $PC l_{3},$ and $C l_{2}$ are a, b and c respectively and total pressure is P then value of $K_{p}$ is:

$\frac{b c}{a} . RT$

$\frac{b}{( a + b + c )} . P$

$\frac{b c . P}{a ( a + b + c )}$

$\frac{c}{( a + b + c )} . P$

$K_{P} = \frac{P ^{'} PC l _{3} \times P ^{'} C l _{2}}{P ^{'} PC l _{5}}$ $= \frac{\frac{b}{( a + b + c )} . P \times \frac{c}{( a + b + c )} \times P}{\frac{a}{( a + b + c )} P}$ $K_{p} = \frac{b c . P}{a ( a + b + c )}$ $A ce t y l e n e C H \equiv C H H_{2} N i C H_{2} = C H_{2}$

Q. PCl5​PCl3​+Cl2​ in this reversible reaction the moles of PCl5​, PCl3​, and Cl2​ are a, b and c respectively and total pressure is P then value of Kp​ is:

abc​.RT

(a+b+c)b​.P

a(a+b+c)bc.P​

(a+b+c)c​.P