Question

$P{b}_3{O}_4+4HN{O}_3\to 2Pb(N{O}_3{)}_2+Pb{O}_2+2H_{2}O$ Which is true about the lead ions in $P{b}_3{O}_4$ ?

• A. $P{b}^{2+}$ reacts with $HN{O}_3$ to give lead nitrate.
• B. $P{b}^{4+}$ reacts with $HN{O}_3$ to give lead nitrate.
• C. $P{b}^{2+}$ reacts with $HN{O}_3$ to give $Pb{O}_2$
• D. $P{b}^{4+}$ reacts with $HN{O}_3$ to give $Pb{O}_2$

Answer 1

Answer: (A)

$P{b}_3{O}_4$ is a mixture of $Pb{O}_2+PbO$ and only $PbO$ i.e., $P{b}^2+$ reacts with $HN{O}_3$ to form $Pb{\left(N{O}_3\right)}_2$.