PA and PB are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If xA represents the mole fraction the total pressure of the solution will be :

Question

PA and PB are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If xA represents the mole fraction the total pressure of the solution will be : (A) PA + xA(PA - PB) (B) PB + xA(PB - PA) (C) PB + xA(PA - PB) (D) PA + xA(PB - PA)

Tardigrade Admin · Accepted Answer

Total pressure PT = PA + PB now PA = PA xA PB = PB xB Substituting the values of PA and PB in eq. (i) PT = PA xA + PB xB [xA + xB = 1 or xA = 1 - xB or xB = 1 - xA] = PAxA+PB -PBxA ∴ PT = PB + xA (PA - PB)

Q. $P_{A}$ and $P_{B}$ are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If $x_{A}$ represents the mole fraction the total pressure of the solution will be :

$P_{A} + x_{A} (P_{A} - P_{B})$

$P_{B} + x_{A} (P_{B} - P_{A})$

$P_{B} + x_{A} (P_{A} - P_{B})$

$P_{A} + x_{A} (P_{B} - P_{A})$

Q. PA​ and PB​ are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If xA​ represents the mole fraction the total pressure of the solution will be :

PA​+xA​(PA​−PB​)

PB​+xA​(PB​−PA​)

PB​+xA​(PA​−PB​)

PA​+xA​(PB​−PA​)

Total pressure PT​=PA​+PB​ now PA​=PA​xA​ PB​=PB​xB​ Substituting the values of PA​ and PB​ in eq. (i) PT​=PA​xA​+PB​xB​ [xA​+xB​=1orxA​=1−xB​orxB​=1−xA​] =PA​xA​+PB​−PB​xA​ ∴ PT​=PB​+xA​(PA​−PB​)

Q. $P_{A}$ and $P_{B}$ are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If $x_{A}$ represents the mole fraction the total pressure of the solution will be :

$P_{A} + x_{A} (P_{A} - P_{B})$

$P_{B} + x_{A} (P_{B} - P_{A})$

$P_{B} + x_{A} (P_{A} - P_{B})$

$P_{A} + x_{A} (P_{B} - P_{A})$