Question

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below



The energy involved in the conversion of $\frac{1}{2}C{l}_2(g)$ to ${\left(Cl\right)}^{-}(aq)$ (Using the data)

${\text{ΔH}}_{\text{diss}}{\text{Cl}}_{\text{2}}\text{=240}\text{kJ}{\text{mol}}^{-1}$

${\text{ΔH}}_{\text{eg}}\text{Cl= -349}\text{kJ}{\text{mol}}^{-1}$

${\text{ΔH}}_{\text{hyd}}\text{Cl= -381}\text{kJ}{\text{mol}}^{-1}$

• A. $+152kJmo{l}^{-1}$
• B. $-610kJmo{l}^{-1}$
• C. $-850kJmo{l}^{-1}$
• D. $+120kJmo{l}^{-1}$

Answer 1

Answer: (B)

$\frac{1}{2}C{l}_2(g)\to C{l}^{-}(aq)$

$\Delta \text{H}=\frac{1}{2}\Delta {\left(\text{H}\right)}_{\text{diss}}({\left(\text{Cl}\right)}_{\text{2}})+\Delta {\left(\text{H}\right)}_{\text{eg}}\text{Cl}+\Delta {\left(\text{H}\right)}_{\text{hyd}}({\left(\text{Cl}\right)}^{-})$

$=\frac{240}{2}-349-381$

$=-610kJmo{l}^{-1}$