Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below (1/2)(Cl)2(g) overset(1/2) Δ Hdiss (Cl)2 arrow Cl(g) oversetΔ Heg Cl arrow (Cl)-(g) oversetΔ Hhyd Cl arrow (Cl)-(aq) The energy involved in the conversion of (1/2)Cl2(.g.) to (C l)-(.aq.) (Using the data) textÎH textdiss textCl text2 text=240 textkJ textmol- 1 textÎH texteg textCl= -349 textkJ textmol- 1 textÎH texthyd textCl= -381 textkJ textmol- 1

Question

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below (1/2)(Cl)2(g) overset(1/2) Δ Hdiss (Cl)2 arrow Cl(g) oversetΔ Heg Cl arrow (Cl)-(g) oversetΔ Hhyd Cl arrow (Cl)-(aq) The energy involved in the conversion of (1/2)Cl2(.g.) to (C l)-(.aq.) (Using the data) textÎH textdiss textCl text2 text=240 textkJ textmol- 1 textÎH texteg textCl= -349 textkJ textmol- 1 textÎH texthyd textCl= -381 textkJ textmol- 1 (A) +152 kJ mol- 1 (B) -610 kJ mol- 1 (C) -850 kJ mol- 1 (D) +120 kJ mol- 1

Tardigrade Admin · Accepted Answer

(1/2)Cl2(.g.) arrow Cl-(.aq.) Δ textH = (1/2) Δ ( textH) textdiss (. ( textCl) text2 .) + Δ ( textH) texteg textCl + Δ ( textH) texthyd (. ( textCl)- .) =(240/2)-349-381 =-610 kJ mol- 1

$+ 152 k J m o l^{- 1}$

$- 610 k J m o l^{- 1}$

$- 850 k J m o l^{- 1}$

$+ 120 k J m o l^{- 1}$

$\frac{1}{2} C l_{2} (g) \to C l^{-} (a q)$
$Δ H = \frac{1}{2} Δ (H)_{diss} ((Cl)_{2}) + Δ (H)_{eg} Cl + Δ (H)_{hyd} ((Cl)^{-})$
$= \frac{240}{2} - 349 - 381$
$= - 610 k J m o l^{- 1}$

+152kJmol−1

−610kJmol−1

−850kJmol−1

+120kJmol−1

21​Cl2​(g)→Cl−(aq) ΔH=21​Δ(H)diss​((Cl)2​)+Δ(H)eg​Cl+Δ(H)hyd​((Cl)−) =2240​−349−381 =−610kJmol−1

$+ 152 k J m o l^{- 1}$

$- 610 k J m o l^{- 1}$

$- 850 k J m o l^{- 1}$

$+ 120 k J m o l^{- 1}$

$\frac{1}{2} C l_{2} (g) \to C l^{-} (a q)$
$Δ H = \frac{1}{2} Δ (H)_{diss} ((Cl)_{2}) + Δ (H)_{eg} Cl + Δ (H)_{hyd} ((Cl)^{-})$
$= \frac{240}{2} - 349 - 381$
$= - 610 k J m o l^{- 1}$