Oxidation state of oxygen in compounds OF 2 and Na 2 O respectively are

Question

Oxidation state of oxygen in compounds OF 2 and Na 2 O respectively are (A) +2,-2 (B) -2,+2 (C) -2,-1 (D) +1,-1

Tardigrade Admin · Accepted Answer

OF 2, here EN of fluorine is more than oxygen. So, oxidation state of fluorine =-1 and oxidation state of oxygen =+2 In Na 2 O, oxygen has more electronegative value than sodium, So, oxidation state of oxygen =-2 and oxidation state of Na =+1

Q. Oxidation state of oxygen in compounds $O F_{2}$ and $N a_{2} O$ respectively are

$+ 2, - 2$

$- 2, + 2$

$- 2, - 1$

$+ 1, - 1$

$O F_{2}$ , here EN of fluorine is more than oxygen.
So, oxidation state of fluorine $= - 1$
and oxidation state of oxygen $= + 2$
In $N a_{2} O$ , oxygen has more electronegative value than sodium,
So, oxidation state of oxygen $= - 2$
and oxidation state of $N a = + 1$

Q. Oxidation state of oxygen in compounds OF2​ and Na2​O respectively are

+2,−2

−2,+2

−2,−1

+1,−1