Q. Oxidation state of chlorine in perchloric acid is

1521 242 Redox Reactions Report Error

A

$- 1$

18%

B

$0$

8%

C

$- 7$

5%

D

$+ 7$

69%

Solution:

$H C * l O_{4}$
$1 + x - 2 \times 4 = 0.1 + x - 8 = 0$
$x = 8 - 1 = + 7$ oxidation state.