Oxidation number of P in P4,PH3 &NaH2PO2 respectively are :-

Question

Oxidation number of P in P4,PH3 &NaH2PO2 respectively are :- (A) 0,-3,+1 (B) 0,-3,-1 (C) 0,+3,-1 (D) 0,+3,+1

Tardigrade Admin · Accepted Answer

P4 arrow O⋅ N=0 (PH)3 arrow x+3(.+1.)=0 x=-3 (NaH)2(PO)2 arrow (.+1.)+2(.+1.)+x+2(.-2.)=0 x=+1

Q. Oxidation number of $P$ in $P_{4}, P H_{3} & N a H_{2} P O_{2}$ respectively are :-