Question

Oxidation number of osmium (Os) in $Os{O}_4$ is

• A. $+8$
• B. $+6$
• C. $+7$
• D. $+4$

Answer 1

Answer: (A)

$\stackrel{\ast }{O}s{O}_4$
$x+4(-2)=0$
$x-8=0$
$x=+8.$