Question

Oxidation number of nitrogen in $NaN{O}_2$ is

• A. $+2$
• B. $+4$
• C. $+3$
• D. $-3$

Answer 1

Answer: (C)

Let the oxidation number of N in $NaN{O}_2$ be x $+1+x+(-2)\times 2=0$ $1+x-4=0;x=+3$