Question

Oxidation number of 'N' in $N_{3}H$ (hydrazoic acid) is:

• A. $-1/3$
• B. +3
• C. 0
• D. -3

Answer 1

Answer: (A)

$N_{3}H$ (hydrazoic acid) let the oxidation state of $N$ be $x$

$+3+1=0$

$3x=-1$

$x=-1/3$