Q. Oxidation number of $N$ in $N_{2} O$ is :

290 160 NTA AbhyasNTA Abhyas 2020 Report Error

A

$- 2, + 2$

B

$0, + 2$

C

$- 3, + 3$

D

$- 3, - 3$

Solution:

$N_{2} O ⎣ ⎡ \cdot N \cdot 0 \oplus = N + 2 = O - 2 ⎦ ⎤$