Q. Oxidation number of $M n$ in $M n O_{4}^{-}$ ion is

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A

$+ 1$

B

$- 7$

C

$- 1$

D

$+ 7$

Solution:

Let the oxidation number of $M n$ is $x$ . $M n O_{4} \Rightarrow x + 4 \times (- 2) = - 1$ $x - 8 = - 1$ $x = - 1 + 8$ $x = + 7$