Question

Oxidation number of Cr in $Cr{O}_5$ is

• A. + 10
• B. + 8
• C. + 6
• D. + 4

Answer 1

Answer: (C)

The structure of
$Cr{O}_5$ is as
Let the oxidation number of Cr is $x$
$x+1(-2)+4(-1)=0$
$x-2-4=0$
$x=+6$