Orange light of wavelength 6000 × 10-10 m in illuminates a single slit of width 0.6 × 10-4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is .

Question

Orange light of wavelength 6000 × 10-10 m in illuminates a single slit of width 0.6 × 10-4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Condition for minimum d sinθ =n λ ∴ sin θ=(n λ/d)<1 n <( d /λ)=(6 × 10-5/6 × 10-7)=100 ∴ Total number of minima on one side =99 Total number of minima =198

Q. Orange light of wavelength $6000 \times 1 0^{- 10} m$ in illuminates a single slit of width $0.6 \times 1 0^{- 4} m$ . The maximum possible number of diffraction minima produced on both sides of the central maximum is _______.

Condition for minimum
$d s in θ = nλ$
$∴ sin θ = \frac{nλ}{d} < 1$
$n < \frac{d}{λ} = \frac{6 \times 1 0 ^{- 5}}{6 \times 1 0 ^{- 7}} = 100$
$∴$ Total number of minima on one side $= 99$
Total number of minima $= 198$

Q. Orange light of wavelength 6000×10−10m in illuminates a single slit of width 0.6×10−4m. The maximum possible number of diffraction minima produced on both sides of the central maximum is _______.

Condition for minimum dsinθ=nλ ∴sinθ=dnλ​<1 n<λd​=6×10−76×10−5​=100 ∴ Total number of minima on one side =99 Total number of minima =198

Q. Orange light of wavelength $6000 \times 1 0^{- 10} m$ in illuminates a single slit of width $0.6 \times 1 0^{- 4} m$ . The maximum possible number of diffraction minima produced on both sides of the central maximum is _______.

Condition for minimum
$d s in θ = nλ$
$∴ sin θ = \frac{nλ}{d} < 1$
$n < \frac{d}{λ} = \frac{6 \times 1 0 ^{- 5}}{6 \times 1 0 ^{- 7}} = 100$
$∴$ Total number of minima on one side $= 99$
Total number of minima $= 198$