Optical axis of a thin equi-convex lens is the x-axis. The co-ordinates of a point object and its image are (10 cm, 1 cm ) and (100 cm ,-2 cm ), respectively.

Question

Optical axis of a thin equi-convex lens is the x-axis. The co-ordinates of a point object and its image are (10 cm, 1 cm ) and (100 cm ,-2 cm ), respectively. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let the position of, lens be x. ∴ u=-(x-10), v=+(100-x) h1=-2 cm , ho=1 cm (v/u)=(hI/h0) On solving, x=40 cm

Q. Optical axis of a thin equi-convex lens is the $x$ -axis. The co-ordinates of a point object and its image are $(10 c m$ , $1 c m)$ and $(100 c m, - 2 c m)$ , respectively.

Let the position of, lens be $x$ .
$∴ u = - (x - 10), v = + (100 - x)$
$h_{1} = - 2 c m, h_{o} = 1 c m$
$\frac{v}{u} = \frac{h _{I}}{h _{0}}$
On solving, $x = 40 c m$

Q. Optical axis of a thin equi-convex lens is the x-axis. The co-ordinates of a point object and its image are (10cm, 1cm) and (100cm,−2cm), respectively.

Let the position of, lens be x. ∴u=−(x−10),v=+(100−x) h1​=−2cm,ho​=1cm uv​=h0​hI​​ On solving, x=40cm

Q. Optical axis of a thin equi-convex lens is the $x$ -axis. The co-ordinates of a point object and its image are $(10 c m$ , $1 c m)$ and $(100 c m, - 2 c m)$ , respectively.

Let the position of, lens be $x$ .
$∴ u = - (x - 10), v = + (100 - x)$
$h_{1} = - 2 c m, h_{o} = 1 c m$
$\frac{v}{u} = \frac{h _{I}}{h _{0}}$
On solving, $x = 40 c m$