Question

One mole of nitrogen gas on reaction with $3.01\times 10^{23}$ molecules of hydrogen gas produces

• A. one mole of ammonia
• B. $2.0\times 10^{23}$ molecules of ammonia
• C. 2 moles of ammonia
• D. $3.01\times 10^{23}$ molecules of ammonia

Answer 1

Answer: (B)

$N_2+3H_2\rightleftharpoons 2N{H}_3$
$6.022\times 10^{23}$ molecules of $H_2=1$ mole
$\therefore 3.011\times 10^{23}$ molecules of $H_2=0.5$ mole.
$3$ moles of $H_2$ reacts with $2$ moles of $N{H}_3$.
So, $1$ mole of $H_2$ reacts $=\frac{2}{3}$ moles of $N{H}_3$.
$\therefore 0.5$ mole of $H_2\text{ react with }\frac{2}{3}\times 0.5$
$=\frac{1}{3}mole$
$1$ mole of $N{H}_3$ contains $6.022\times 10^{23}$ molecules.
So, $\frac{1}{3}$ mole of $N{H}_3$ will have
$=6.022\times 10^{23}\times \frac{1}{3}$
$=2.0\times 10^{23}$ molecules.