One mole of any substance contains 6.022 × 1023 atoms/molecules. Number of molecules of H2SO4 present in 100 mL of 0.02 M H2SO4 solution is molecules.

Question

One mole of any substance contains 6.022 × 1023 atoms/molecules. Number of molecules of H2SO4 present in 100 mL of 0.02 M H2SO4 solution is molecules. (A) 12.044×1020 (B) 6.022×1023 (C) 1×1023 (D) 12.044×1023

Tardigrade Admin · Accepted Answer

Molarity =( textNo. of moles of solute × 1000/ textVolume of solutions (in mL)) because 1 M H2 SO4 contains 1 mole of H2SO4 i n 1000 mL of solutions ∴ 0.02 M H2SO4 in 100 mL of solution contains ( 0.02× 100/1000) = 2× × 10-3 mol = 2 × 10-3 × 6.022× 1023 = 12.044× 1020 molecules

Q. One mole of any substance contains $6.022 \times 1 0^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in $100 m L$ of $0.02 M H_{2} S O_{4}$ solution is _______molecules.

$12.044 \times 1 0^{20}$

$6.022 \times 1 0^{23}$

$1 \times 1 0^{23}$

$12.044 \times 1 0^{23}$

Q. One mole of any substance contains 6.022×1023 atoms/molecules. Number of molecules of H2​SO4​ present in 100mL of 0.02MH2​SO4​ solution is _______molecules.

12.044×1020

6.022×1023

1×1023

12.044×1023

Molarity =Volume of solutions (in mL)No. of moles of solute ×1000​ because1MH2​SO4​ contains 1 mole of H2​SO4​ i n 1000mL of solutions ∴0.02MH2​SO4​ in 100mL of solution contains 10000.02×100​=2××10−3 mol =2×10−3×6.022×1023 =12.044×1020 molecules

Q. One mole of any substance contains $6.022 \times 1 0^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in $100 m L$ of $0.02 M H_{2} S O_{4}$ solution is _______molecules.

$12.044 \times 1 0^{20}$

$6.022 \times 1 0^{23}$

$1 \times 1 0^{23}$

$12.044 \times 1 0^{23}$