One mole of 1,2-dibromopropane on treatment with X moles of NaNH2 followed by treatment with ethyl bromide gave a 2-pentyne. The value of X is

Question

One mole of 1,2-dibromopropane on treatment with X moles of NaNH2 followed by treatment with ethyl bromide gave a 2-pentyne. The value of X is (A) one (B) two (C) three (D) four

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/0a8e0ec447495623b651a995567cd6c1-.jpeg" /> Total number of moles of NaNH2 = 2 + 1 = 3

Q. One mole of $1$ , $2$ -dibromopropane on treatment with $X$ moles of $N a N H_{2}$ followed by treatment with ethyl bromide gave a $2$ -pentyne. The value of $X$ is

one

two

three

four

Total number of moles of $N a N H_{2} = 2 + 1 = 3$

Q. One mole of 1,2-dibromopropane on treatment with X moles of NaNH2​ followed by treatment with ethyl bromide gave a 2-pentyne. The value of X is

one

two

three

four

Total number of moles of NaNH2​=2+1=3

Q. One mole of $1$ , $2$ -dibromopropane on treatment with $X$ moles of $N a N H_{2}$ followed by treatment with ethyl bromide gave a $2$ -pentyne. The value of $X$ is

Total number of moles of $N a N H_{2} = 2 + 1 = 3$