One gram sample of NH 4 NO 3 is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ / g / deg. What is the molar heat of decomposition for NH 4 NO 3 ?

Question

One gram sample of NH 4 NO 3 is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 K. The heat capacity of the system is 1.23 kJ / g / deg. What is the molar heat of decomposition for NH 4 NO 3 ? (A) -7.53 kJ / mol (B) -398.1 kJ / mol (C) -16.1 kJ / mol (D) -602 kJ / mol

Tardigrade Admin · Accepted Answer

Heat of decomposition, Δ E=m ⋅ s ⋅ Δ T =1 × 1.23 × 6.12=7.5276 kJ Molar heat of decomposition for NH 4 NO 3 =7.5276 × 80=602.2 kJ

Q. One gram sample of $N H_{4} N O_{3}$ is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by $6.12 K$ . The heat capacity of the system is $1.23 k J / g / d e g$ . What is the molar heat of decomposition for $N H_{4} N O_{3}$ ?

$- 7.53 k J / m o l$

$- 398.1 k J / m o l$

$- 16.1 k J / m o l$

$- 602 k J / m o l$

Heat of decomposition, $Δ E = m \cdot s \cdot Δ T$

$= 1 \times 1.23 \times 6.12 = 7.5276 k J$

Molar heat of decomposition for $N H_{4} N O_{3}$

$= 7.5276 \times 80 = 602.2 k J$

Q. One gram sample of NH4​NO3​ is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12K. The heat capacity of the system is 1.23kJ/g/deg. What is the molar heat of decomposition for NH4​NO3​ ?

−7.53kJ/mol

−398.1kJ/mol

−16.1kJ/mol

−602kJ/mol