On the horizontal surface of a truck, a block of mass 1 kg is placed (μ=0.6) and truck is moving with acceleration 5 m / s 2. The frictional force acting on the block will be: (g=10 m / s 2)

Question

On the horizontal surface of a truck, a block of mass 1 kg is placed (μ=0.6) and truck is moving with acceleration 5 m / s 2. The frictional force acting on the block will be: (g=10 m / s 2) (A) 6 N (B) 5.88 N (C) 7 N (D) 9 N

Tardigrade Admin · Accepted Answer

The frictional force acting on the block

f = μ R

but from figure,

R = m g

f = μ m g

Here,

μ = 0.6, m = 1 k g, g = 10 m / s^{2}

∴

f = 0.6 \times 1 \times 10 = 6 N

Due to acceleration of truck, the block experiences a forward force

F = ma = 1 \times 5 = 5 N

Since

f > F,

so block is not displaced from its previous position.

Q. On the horizontal surface of a truck, a block of mass 1kg is placed (μ=0.6) and truck is moving with acceleration 5m/s2. The frictional force acting on the block will be: (g=10m/s2)

6 N

5.88 N

7 N

9 N

The frictional force acting on the block f=μR but from figure, R=mg f=μmg Here, μ=0.6,m=1kg,g=10m/s2 ∴ f=0.6×1×10=6N Due to acceleration of truck, the block experiences a forward force F=ma=1×5=5N Since f>F, so block is not displaced from its previous position.

Q. On the horizontal surface of a truck, a block of mass $1 k g$ is placed $(μ = 0.6)$ and truck is moving with acceleration $5 m / s^{2}$ . The frictional force acting on the block will be: $(g = 10 m / s^{2})$