On the basis of the information available from the reaction, 4 / 3 textAl + textO2 arrow 2 / 3 textAl2 textO3 text; textΔG = - 827 textkJmol- 1 , the minimum e.m.f. required to carry out electrolysis of Al2O3 is (.F=96500 Cmol- 1.)

Question

On the basis of the information available from the reaction, 4 / 3 textAl + textO2 arrow 2 / 3 textAl2 textO3 text; textΔG = - 827 textkJmol- 1 , the minimum e.m.f. required to carry out electrolysis of Al2O3 is (.F=96500 Cmol- 1.) (A) 2.14 V (B) 4.28 V (C) 6.42 V (D) 8.56 V

Tardigrade Admin · Accepted Answer

Δ G=-nFE° E° =(Δ G/- n F)-(- 827000/- 4 × 96500)=2.14

Q. On the basis of the information available from the reaction,
$4/3 Al + O_{2} \to 2/3 Al_{2} O_{3}; ΔG = - 827 kJmol^{- 1}$ , the minimum e.m.f. required to carry out electrolysis of $A l_{2} O_{3}$ is $(F = 96500 C m o l^{- 1})$

2.14 V

4.28 V

6.42 V

8.56 V

$Δ G = - n F E^{\circ}$
$E^{\circ} = \frac{Δ G}{- n F} - \frac{- 827000}{- 4 \times 96500} = 2.14$

Q. On the basis of the information available from the reaction, 4/3Al+O2​→2/3Al2​O3​;ΔG=−827kJmol−1 , the minimum e.m.f. required to carry out electrolysis of Al2​O3​ is (F=96500Cmol−1)