On passing H2S into a solution containing both Zn2+ and Cu2+ in acidic medium, only CuS gets precipitated. This is because

Question

On passing H2S into a solution containing both Zn2+ and Cu2+ in acidic medium, only CuS gets precipitated. This is because (A) Ksp of CuS < Ksp of ZnS (B) Ksp of CuS = Ksp of ZnS (C) Ksp of CuS > Ksp of ZnS (D) CuS is more stable than ZnS.

Tardigrade Admin · Accepted Answer

Since the solubility product of CuS is less than that of ZnS, CuS gets precipitated. K sp ( CuS )< K sp ( ZnS ) K sp ( CuS )=8 × 10-37 K sp ( Zn S )=1.2 × 10-23

Q. On passing $H_{2} S$ into a solution containing both $Z n^{2 +}$ and $C u^{2 +}$ in acidic medium, only $C u S$ gets precipitated. This is because

$K_{s p}$ of $C u S < K_{s p}$ of $Z n S$

$K_{s p}$ of $C u S = K_{s p}$ of $Z n S$

$K_{s p}$ of $C u S > K_{s p}$ of $Z n S$

$C u S$ is more stable than $Z n S$ .

Since the solubility product of $C u S$ is less than that of $Z n S$ , CuS gets precipitated.
$K_{s p} (C u S) < K_{s p} (Z n S)$
$K_{s p} (C u S) = 8 \times 1 0^{- 37}$
$K_{s p} (Z n S) = 1.2 \times 1 0^{- 23}$

Q. On passing H2​S into a solution containing both Zn2+ and Cu2+ in acidic medium, only CuS gets precipitated. This is because

Ksp​ of CuS<Ksp​ of ZnS

Ksp​ of CuS=Ksp​ of ZnS

Ksp​ of CuS>Ksp​ of ZnS

CuS is more stable than ZnS.