Question

On controlled hydrolysis and condensation, $R_{3}SiCl$ yields

• A. $R_{3}Si-O-Si{R}_3$
• B. ${(-R_{3}Si-O-Si{R}_3-)}_n$
• C. $R_{3}SiOH$
• D. $-\underset{\underset{-\underset{|}{\stackrel{|}{\mathrm{Si}}}-\text{O}}{\stackrel{|}{O}}}{\stackrel{\begin{array}{c}\text{R}\\ |\end{array}}{\mathrm{Si}}}-\text{O}-\underset{\underset{-\underset{|}{\stackrel{|}{\mathrm{Si}}}-}{\stackrel{|}{O}}}{\stackrel{\begin{array}{c}\text{R}\\ |\end{array}}{\mathrm{Si}}}-$

Answer 1

Answer: (A)

$R_{3}SiCl$ on hydrolysis can only form a dimer. $R_{3}SiCl\stackrel{H_{2}O}{\to }{R}_{3}SiOH$ $R_{3}SiOH+R_{3}SiOH\stackrel{-H_{2}O}{\to }{R}_{3}Si-O-Si{R}_3$