Number of solutions of the equation | sin θ sin 2 θ sin 3 θ sin 2 θ sin 3 θ sin θ sin 3 θ sin θ sin 2 θ|=0 in [0,2 π] is

Question

Number of solutions of the equation | sin θ sin 2 θ sin 3 θ sin 2 θ sin 3 θ sin θ sin 3 θ sin θ sin 2 θ|=0 in [0,2 π] is (A) 3 (B) 5 (C) 7 (D) 9

Tardigrade Admin · Accepted Answer

We have, ( sin θ+ sin 2 θ+ sin 3 θ) ⋅[( sin θ- sin 2 θ)2+( sin 2 θ- sin 3 θ)2+( sin 3 θ- sin θ)2]=0

Q. Number of solutions of the equation $∣ ∣ sin θ sin 2 θ sin 3 θ sin 2 θ sin 3 θ sin θ sin 3 θ sin θ sin 2 θ ∣ ∣ = 0$ in $[0, 2 π]$ is