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Question
Mathematics
Number of real values of x satisfying the equation √x2-6 x+9+√x2-6 x+6=1 text is
Q. Number of real values of
x
satisfying the equation
x
2
−
6
x
+
9
+
x
2
−
6
x
+
6
=
1
is
289
100
Complex Numbers and Quadratic Equations
Report Error
A
0
B
1
C
2
D
more than 2
Solution:
(
x
2
−
6
x
+
9
)
−
(
x
2
−
6
x
+
6
)
=
3
x
2
−
6
x
+
9
−
x
2
−
6
x
+
6
=
3
adding
x
2
−
6
x
+
9
=
2
x
2
−
6
x
+
9
=
4
x
2
−
6
x
+
5
=
0
(
x
−
5
)
(
x
−
1
)
=
0
⇒
x
=
1
or
5
but none satisfies.