Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Number of points of non-differentiability of the function f(x)=x(x-1)|ex-1| ⋅|x-3|3 on x ∈(-∞, ∞) is equal to .
Q. Number of points of non-differentiability of the function
f
(
x
)
=
x
(
x
−
1
)
∣
e
x
−
1
∣
⋅
∣
x
−
3
∣
3
on
x
∈
(
−
∞
,
∞
)
is equal to ______.
2613
201
Continuity and Differentiability
Report Error
Answer:
0
Solution:
f
(
x
)
=
x
(
x
−
1
)
∣
e
x
−
11
⋅
∣
x
−
3
∣
3
Here,
x
=
0
and 3 are repeated roots of
f
(
x
)
=
0
So, there is no point where
f
(
x
)
is non-differentiable for all
x
∈
R