Question

Number of divisors of the form $(4n+2),n\ge 0$ of the integer $240$ is

• A. 4
• B. 8
• C. 10
• D. 3

Answer 1

Answer: (A)

Since, $240=2^4\cdot 3\cdot 5$
$\therefore$Total number of divisors $=(4+1)(2)(2)=20$
Out of these $2,6,10$, and $30$ are of the form $4n+2$.
Therefore, (a) is the answer.