Number of atoms in 558.5 g of Fe (At. mass of Fe= 55.85 g mol1) is

Question

Number of atoms in 558.5 g of Fe (At. mass of Fe= 55.85 g mol1) is (A) Twice that in 60 g carbon (B) 6.023 × 1022 (C) Half in 8 g He (D) 558.5 × 6.023 × 1023

Tardigrade Admin · Accepted Answer

Moles of Fe = (558.5/55.85) = 10; Moles of C = (60/12) = 5

Q. Number of atoms in 558.5 g of Fe (At. mass of Fe= 55.85 g $m o l^{_{1}}$ ) is

Twice that in $60 g$ carbon

$6.023 \times 1 0^{22}$

Half in $8 g$ He

$558.5 \times 6.023 \times 1 0^{23}$

Moles of $F e = \frac{558.5}{55.85} = 10$ ;
Moles of $C = \frac{60}{12} = 5$

Q. Number of atoms in 558.5 g of Fe (At. mass of Fe= 55.85 g mol1​) is

Twice that in 60g carbon

6.023×1022

Half in 8g He

558.5×6.023×1023