Question

Nucleophilic attack on carbonyl carbon changes its hybridisation from

• A. $sp$ to $s{p}^2$
• B. $s{p}^2$ to $s{p}^3$
• C. $s{p}^3$ to $s{p}^2$
• D. $sp$ to $s{p}^3$

Answer 1

Answer: (B)

Correct answer is (b) $s{p}^2$ to $s{p}^3$