Na23 is more stable isotope of Na . The process by which 11Na24 can undergo radioactive decay is

Question

Na23 is more stable isotope of Na . The process by which 11Na24 can undergo radioactive decay is (A)  β -rays (B)  α -rays (C)  β + -rays (D)  &gamma; -rays

Tardigrade Admin · Accepted Answer

underset textless stable11Na24 → underset textStable11Na23 + underset textneutron0n1 The neutron on decomposition gives a prof and a β -particle (-1e0) 0n1 → underset textproton1H1 + undersetβ- textparticle-1e0 . Hence, 11Na24 gets changed into 11Na23 means of β -emission.

Q. $N a^{23}$ is more stable isotope of $N a$ . The process by which $_{11} N a^{24}$ can undergo radioactive decay is

$β$ -rays

$α$ -rays

$β^{+}$ -rays

$γ$ -rays

$less stable_{11} N a^{24} \to Stable_{11} N a^{23} + neutron_{0} n^{1}$
The neutron on decomposition gives a prof
and a $β$ -particle $(_{- 1} e^{0})_{0} n^{1} \to proton_{1} H^{1} + β - particle_{- 1} e^{0}$ .
Hence, $_{11} N a^{24}$ gets changed into $_{11} N a^{23}$ means of $β$ -emission.

Q. Na23 is more stable isotope of Na . The process by which 11​Na24 can undergo radioactive decay is

β -rays

α -rays

β+ -rays

γ -rays