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Tardigrade
Question
Chemistry
n factor fo FeC 2 O 4 during its oxidation by acidified KMnO 4 is.
Q.
n
factor fo
F
e
C
2
O
4
during its oxidation by acidified
K
M
n
O
4
is.
157
226
Redox Reactions
Report Error
Answer:
3
Solution:
F
e
C
2
O
4
→
F
e
3
+
+
C
O
2
+
3
e
n
factor
=
3