Moment of inertia of wheel about the axis of 4 rotation is 3 MKS units. Its kinetic energy will be 600 J, if period of rotation is (in seconds)

Question

Moment of inertia of wheel about the axis of 4 rotation is 3 MKS units. Its kinetic energy will be 600 J, if period of rotation is (in seconds) (A)  π  (B)  (π /5)  (C)  (π /10)  (D)  2π

Tardigrade Admin · Accepted Answer

E =(1/2) l ω2 ω=√(2 E /1)-√(2 × 600/3)=20 ω=(2 π/ T )=20 ⇒ T =(π/10)

Q. Moment of inertia of wheel about the axis of 4 rotation is 3 MKS units. Its kinetic energy will be 600 J, if period of rotation is (in seconds)

$π$

$\frac{π}{5}$

$\frac{π}{10}$

$2 π$

$E = \frac{1}{2} l ω^{2}$
$ω = \frac{2 E}{1} - \frac{2 \times 600}{3} = 20$
$ω = \frac{2 π}{T} = 20 \Rightarrow T = \frac{π}{10}$

Q. Moment of inertia of wheel about the axis of 4 rotation is 3 MKS units. Its kinetic energy will be 600 J, if period of rotation is (in seconds)

π

5π​

10π​

2π

E=21​lω2 ω=12E​​−32×600​​=20 ω=T2π​=20⇒T=10π​

$π$

$\frac{π}{5}$

$\frac{π}{10}$

$2 π$

$E = \frac{1}{2} l ω^{2}$
$ω = \frac{2 E}{1} - \frac{2 \times 600}{3} = 20$
$ω = \frac{2 π}{T} = 20 \Rightarrow T = \frac{π}{10}$