Question

Molarity of $0.2N{H}_{2}S{O}_4$ is

• A. 0.2
• B. 0.4
• C. 0.6
• D. 0.1

Answer 1

Answer: (D)

Molarity $=\frac{\text{ Normality }}{n-\text{ factor }}$
For $H_{2}S{O}_4,n$-factor is 2
Molarity $=\frac{\text{ Normality }}{2}$
Molarity $=\frac{0.2}{2}$
Molarity $=0.1M$