Question

Molar conductivity of a solution of an electrolyte $A{B}_2$ is $160oh{m}^{-1}c{m}^{2}mo{l}^{-1}$ . If it ionizes as $A{B}_2\to A^{+2}+2B^{-1}$ . Its equivalent conductivity will be

• A. $150oh{m}^{-1}c{m}^{-1}mo{l}^{-1}$
• B. $\text{75 }oh{m}^{-1}c{m}^{-1}mo{l}^{-1}$
• C. $\text{80 }oh{m}^{-1}c{m}^{-1}mo{l}^{-1}$
• D. all of the above

Answer 1

Answer: (C)

: Molar conductivity, ${\wedge }_m=160oh{m}^{-1}c{m}^2/mol$ ${\wedge }_m=\frac{k\times 1000}{Molarity}$ ${\wedge }_{eq}=\frac{k\times 1000}{Normality}$ $\frac{{\wedge }_{eq}}{{\wedge }_m}=\frac{Molarity}{Normality}$ ${\wedge }_{eq}=\frac{{\wedge }_m\times numberofmolesperlitre}{numberofgmequivalentsperlitre}$ ${\wedge }_{eq}=\frac{160\times eq.wt}{mol.wt.}$ $=\frac{160\times mol.wt.}{2\times mol.wt}$ $=80oh{m}^{-1}c{m}^{2}e{q}^{-1}$ .