Molar conductances of BaCl2, H2SO4 and HCl at infinite dilutions are x1, x2 and x3, respectively. Equivalent conductance of BaSO4 at infinite dilution will be:

Question

Molar conductances of BaCl2, H2SO4 and HCl at infinite dilutions are x1, x2 and x3, respectively. Equivalent conductance of BaSO4 at infinite dilution will be: (A) ([x1+x2 -x3 ]/2) (B) ([x1-x2 -x3 ]/2) (C) 2(x1 +x2 -2x3) (D) ([x1+x2 -2x3 ]/2)

Tardigrade Admin · Accepted Answer

Lambdam,BaCl2 = Lambdam Ba2++2 Lambdam cl- x1 Lambdam H2SO4 =2 LambdamH++ Lambdam SO-4 x2 Lambdam HCl = LambdamH+ + Lambdam Cl- x3] ×2 ∴ Lambdam, BaSO4 =(x1+x2-2x3) :⇒ : Lambda eq. :BaSO4 :=( Lambda m, :BaSO4/ textTotal charge (cation/anion)) : Lambda eq, :BaSO4 :=([x1 :+x2 :-2x3]/2)

Q. Molar conductances of $B a C l_{2}, H_{2} S O_{4}$ and $H Cl$ at infinite dilutions are $x_{1}, x_{2}$ and $x_{3}$ , respectively. Equivalent conductance of $B a S O_{4}$ at infinite dilution will be:

$\frac{[ x _{1} + x _{2} - x _{3} ]}{2}$

$\frac{[ x _{1} - x _{2} - x _{3} ]}{2}$

$2 (x_{1} + x_{2} - 2 x_{3})$

$\frac{[ x _{1} + x _{2} - 2 x _{3} ]}{2}$

Q. Molar conductances of BaCl2​,H2​SO4​ and HCl at infinite dilutions are x1​,x2​ and x3​, respectively. Equivalent conductance of BaSO4​ at infinite dilution will be:

2[x1​+x2​−x3​]​

2[x1​−x2​−x3​]​

2(x1​+x2​−2x3​)

2[x1​+x2​−2x3​]​

Λm,BaCl2​​=ΛmBa2+​+2Λmcl−​x1​ ΛmH2​SO4​​=2ΛmH+​+ΛmSO4−​​x2​ ΛmHCl​=ΛmH+​+ΛmCl−​x3​]×2 ∴Λm,BaSO4​​=(x1​+x2​−2x3​) ⇒Λeq​.BaSO4​=Total charge (cation/anion)Λm,BaSO4​​​ Λeq,BaSO4​​=2[x1​+x2​−2x3​]​

Q. Molar conductances of $B a C l_{2}, H_{2} S O_{4}$ and $H Cl$ at infinite dilutions are $x_{1}, x_{2}$ and $x_{3}$ , respectively. Equivalent conductance of $B a S O_{4}$ at infinite dilution will be:

$\frac{[ x _{1} + x _{2} - x _{3} ]}{2}$

$\frac{[ x _{1} - x _{2} - x _{3} ]}{2}$

$2 (x_{1} + x_{2} - 2 x_{3})$

$\frac{[ x _{1} + x _{2} - 2 x _{3} ]}{2}$