Molal depression constant kf is always greater than molal elevation constant kb for any solvent. It is because

Question

Molal depression constant kf is always greater than molal elevation constant kb for any solvent. It is because (A) the magnitude of Enthalpy of vapourisation is greater than the magnitude of Enthalpy of Fusion. (B) kf and kb are inversely proportional to Enthalpy of vapourisation and Enthalpy of fusion respectively. (C) kf and kb are inversely proportional to Enthalpy of fusion and Enthalpy of vapourisation respectively. (D) of both (1) and (3) statements.

Tardigrade Admin · Accepted Answer

kf=(R Tf2 M/1000 Δ H text filsion ) and kb=(R Tb2 M/1000 Δ H text vapourisation ) and Δ H text vapourisation >Δ H text filsion

Q. Molal depression constant $k_{f}$ is always greater than molal elevation constant $k_{b}$ for any solvent. It is because

the magnitude of Enthalpy of vapourisation is greater than the magnitude of Enthalpy of Fusion.

$k_{f}$ and $k_{b}$ are inversely proportional to Enthalpy of vapourisation and Enthalpy of fusion respectively.

$k_{f}$ and $k_{b}$ are inversely proportional to Enthalpy of fusion and Enthalpy of vapourisation respectively.

of both (1) and (3) statements.

$k_{f} = \frac{R T _{f}^{2} M}{1000Δ H _{filsion}}$ and $k_{b} = \frac{R T _{b}^{2} M}{1000Δ H _{vapourisation}}$ and
$Δ H_{vapourisation} > Δ H_{filsion}$

Q. Molal depression constant kf​ is always greater than molal elevation constant kb​ for any solvent. It is because

the magnitude of Enthalpy of vapourisation is greater than the magnitude of Enthalpy of Fusion.

kf​ and kb​ are inversely proportional to Enthalpy of vapourisation and Enthalpy of fusion respectively.

kf​ and kb​ are inversely proportional to Enthalpy of fusion and Enthalpy of vapourisation respectively.

of both (1) and (3) statements.

kf​=1000ΔHfilsion ​RTf2​M​ and kb​=1000ΔHvapourisation ​RTb2​M​ and ΔHvapourisation ​>ΔHfilsion ​

Q. Molal depression constant $k_{f}$ is always greater than molal elevation constant $k_{b}$ for any solvent. It is because

$k_{f}$ and $k_{b}$ are inversely proportional to Enthalpy of vapourisation and Enthalpy of fusion respectively.

$k_{f}$ and $k_{b}$ are inversely proportional to Enthalpy of fusion and Enthalpy of vapourisation respectively.

$k_{f} = \frac{R T _{f}^{2} M}{1000Δ H _{filsion}}$ and $k_{b} = \frac{R T _{b}^{2} M}{1000Δ H _{vapourisation}}$ and
$Δ H_{vapourisation} > Δ H_{filsion}$